Similarity of Triangles by AAA Criteria:
Theorem : If in two triangles, the corresponding angles are equal, then the corresponding sides are proportional ( i.e., in the same ratio) and hence the triangles are similar.
Given: in ABC and DEF
To Prove :
Construction: Cut DP = Ab and DQ = Ac and Join PQ. Proof: In ABC and DPQ AB = DP [ By Construction ] A = D [ Given] AC = DQ [ By Construction ] Hence ABC DPQ [ By SAS Criteria] B = P and C = Q [C.P. C. T] But B = E [ Given] Hence P = E But they are corresponding angles when PQ and EF are straight lines and Transversal DE cuts them. As they are equal So the lines are parallel Therefore by Basic Proportionality Theorem
Taking Reciprocal both Sides and adding 1 to both sides we get Taking Reciprocal we get replacing DP with AB and DQ with AC as they are equal by construction We get Similary We can prove that And Hence |
Illustration : If AB || CD , prove that Solution: As AB || CD then [ Alternate Interior Angle ] [ Alternate Interior Angle ] [ Vertically Opposite Angle ] Therefore, [ AAA Similarity Criterion] |
In the following figure, . Then by ________________________ criteria. | |||
Right Option : A | |||
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In the following figure, by which criteria? | |||
Right Option : C | |||
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In above figure, by __________________ criteria. | |||
Right Option : D | |||
View Explanation |
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